Lloyd | 2020-04-09 18:59:42 UTC | #1

I usually use C#, but working with a team on a Python implementation of the notifications API & struggling with implementing notifications .

I've created an instance of the Notifications API & have created a channel & am attempting to subscribe to a topic.

print('\n* CREATING CHANNEL') createdChannelOk = False try:

Create a new channel

newChannelresponse = apiinstance.postnotificationschannels()

pprint(newChannel_response)

print(newChannelresponse) createdChannelOk = True except ApiException as e: print("Exception when calling NotificationsApi->postnotifications_channels: %s\n" % e)

if (createdChannelOk): print('\n* SUBSCRIBING TO QUEUE')

channel = str(newChannel_response['id'])

myTopic = 'v2.routing.queues.'+queue_id+'.conversations' print(myTopic) body = [myTopic] # list[ChannelTopic] | Body

try:

Replace the current list of subscriptions with a new list.

apiresponse = apiinstance.putnotificationschannelsubscriptions(newChannelresponse['id'], body) pprint(apiresponse) except ApiException as e: print("Exception when calling NotificationsApi->putnotificationschannelsubscriptions: %s\n" % e)

The channel is created successfully, but I get an error trying to subscribe to the topic

CREATING CHANNEL {'connect_uri': 'wss://streaming.mypurecloud.com.au/channels/streaming-0-80b1gi3gjc4msvd0tcrfg9vcl6', 'expires': datetime.datetime(2020, 4, 10, 18, 47, 17, 858000, tzinfo=tzutc()), 'id': 'streaming-0-80b1gi3gjc4msvd0tcrfg9vcl6'}

SUBSCRIBING TO QUEUE v2.routing.queues.f4bf7a5c-d17a-4020-82f7-9bcf3c061722.conversations Traceback (most recent call last): File "C:/PYRIOS/twilio-auto-tester/pyriosQueueNotifications.py", line 73, in <module> apiresponse = apiinstance.putnotificationschannelsubscriptions(newChannelresponse['id'], body) TypeError: 'Channel' object is not subscriptable

So it appears my use of newChannel_response['id'] is incorrect.

If I copy the ChannelId from the output & hard code it, then the subscription (appears to) works fine.

So my question is how do I use the channel Id from create channel response in the subscription request

Thanks

tim.smith | 2020-04-09 19:06:05 UTC | #2

It should just be newChannel_response.id. The response is an instance of the Channel class, not a dictionary.

Lloyd | 2020-04-09 22:14:35 UTC | #3

Ahh, I'm being a muppet; That worked perfectly!

• Thanks Tim

system | 2020-05-10 22:14:39 UTC | #4

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